1808 United States presidential election in Ohio
1808 United States presidential election in Ohio[edit]
The 1808 United States presidential election in Ohio took place as part of the 1808 United States Presidential Election. Voters chose eight representatives, or electors to the Electoral College, who voted for the President and Vice-President.
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Ohio voted for the Democratic-Republican candidate, James Madison over, the Federalist candidate, Charles Cotesworth Pinckney. Madison won Ohio's eight electoral votes by a margin of 56.89%.
Results[edit]
| 1808 United States presidential election in Ohio[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | James Madison | 11,868 | 78.44% | 3 | |
| Federalist | Charles Cotesworth Pinckney | 3,262 | 21.55% | 0 | |
| Totals | 15,130 | 100.0% | 3 | ||
- ↑ "Ohio 1808 Electoral College". Tufts University. Retrieved 24 March 2020. Unknown parameter
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References[edit]
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